[alibaba/fastjson]反序列化成Integer的疑惑

fastjson版本：尝试过1.2.47/1.2.49，反序列化超限整形为Integer field时，有的跑异常，有的返回一个不可预期的整数。感觉像是一个bug。。。如下代码： static class M { Integer i;

    public Integer getI() {
        return i;
    }

    public void setI(Integer i) {
        this.i = i;
    }
}

public static void main(String[] args) throws IOException {
    String sInt[] = new String[]{"{\"i\":11234564654321321}"
            , "{\"i\":1001234564654321321000000000000000000000}"
            , "{\"i\":100000000000000000000012345646543213210}"
            , "{\"i\":10000000000000000000001234564654321321}"
            , "{\"i\":112345646543213210}"};
    for (String s : sInt) {
        try {
            System.out.println(JSONObject.toJSONString(JSONObject.parseObject(s, M.class)));
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

输出结果： com.alibaba.fastjson.JSONException: parseInt error, field : i at com.alibaba.fastjson.serializer.IntegerCodec.deserialze(IntegerCodec.java:99) at com.alibaba.fastjson.parser.deserializer.DefaultFieldDeserializer.parseField(DefaultFieldDeserializer.java:86) at com.alibaba.fastjson.parser.deserializer.JavaBeanDeserializer.parseField(JavaBeanDeserializer.java:1149) at com.alibaba.fastjson.parser.deserializer.JavaBeanDeserializer.deserialze(JavaBeanDeserializer.java:801) at com.alibaba.fastjson.parser.deserializer.JavaBeanDeserializer.deserialze(JavaBeanDeserializer.java:273) at com.alibaba.fastjson.parser.DefaultJSONParser.parseObject(DefaultJSONParser.java:669) at com.alibaba.fastjson.JSON.parseObject(JSON.java:365) at com.alibaba.fastjson.JSON.parseObject(JSON.java:269) at com.alibaba.fastjson.JSON.parseObject(JSON.java:488) at com.sensetime.ad.senseadx.common.util.TestOkHttp.main(TestOkHttp.java:71) Caused by: java.lang.NumberFormatException: 11234564654321321 at com.alibaba.fastjson.parser.JSONLexerBase.intValue(JSONLexerBase.java:1064) at com.alibaba.fastjson.serializer.IntegerCodec.deserialze(IntegerCodec.java:81) ... 9 more com.alibaba.fastjson.JSONException: parseInt error, field : i at com.alibaba.fastjson.serializer.IntegerCodec.deserialze(IntegerCodec.java:99) at com.alibaba.fastjson.parser.deserializer.DefaultFieldDeserializer.parseField(DefaultFieldDeserializer.java:86) at com.alibaba.fastjson.parser.deserializer.JavaBeanDeserializer.parseField(JavaBeanDeserializer.java:1149) at com.alibaba.fastjson.parser.deserializer.JavaBeanDeserializer.deserialze(JavaBeanDeserializer.java:801) at com.alibaba.fastjson.parser.deserializer.JavaBeanDeserializer.deserialze(JavaBeanDeserializer.java:273) at com.alibaba.fastjson.parser.DefaultJSONParser.parseObject(DefaultJSONParser.java:669) at com.alibaba.fastjson.JSON.parseObject(JSON.java:365) at com.alibaba.fastjson.JSON.parseObject(JSON.java:269) at com.alibaba.fastjson.JSON.parseObject(JSON.java:488) at com.sensetime.ad.senseadx.common.util.TestOkHttp.main(TestOkHttp.java:71) Caused by: java.lang.NumberFormatException: 1001234564654321321000000000000000000000 at com.alibaba.fastjson.parser.JSONLexerBase.intValue(JSONLexerBase.java:1064) at com.alibaba.fastjson.serializer.IntegerCodec.deserialze(IntegerCodec.java:81) ... 9 more com.alibaba.fastjson.JSONException: parseInt error, field : i at com.alibaba.fastjson.serializer.IntegerCodec.deserialze(IntegerCodec.java:99) at com.alibaba.fastjson.parser.deserializer.DefaultFieldDeserializer.parseField(DefaultFieldDeserializer.java:86) at com.alibaba.fastjson.parser.deserializer.JavaBeanDeserializer.parseField(JavaBeanDeserializer.java:1149) at com.alibaba.fastjson.parser.deserializer.JavaBeanDeserializer.deserialze(JavaBeanDeserializer.java:801) at com.alibaba.fastjson.parser.deserializer.JavaBeanDeserializer.deserialze(JavaBeanDeserializer.java:273) at com.alibaba.fastjson.parser.DefaultJSONParser.parseObject(DefaultJSONParser.java:669) at com.alibaba.fastjson.JSON.parseObject(JSON.java:365) at com.alibaba.fastjson.JSON.parseObject(JSON.java:269) at com.alibaba.fastjson.JSON.parseObject(JSON.java:488) at com.sensetime.ad.senseadx.common.util.TestOkHttp.main(TestOkHttp.java:71) Caused by: java.lang.NumberFormatException: 100000000000000000000012345646543213210 at com.alibaba.fastjson.parser.JSONLexerBase.intValue(JSONLexerBase.java:1064) at com.alibaba.fastjson.serializer.IntegerCodec.deserialze(IntegerCodec.java:81) ... 9 more {"i":2074889897} {"i":843387546}

nackinggit

I found the error too

prepared48

今天同样遇到这种问题，即将一个时间戳类型定义了Integer类型，在JSON反序列化该字段时，对于windows系统会直接报：parseInt error(因为超过了int的最大值)；但是对于Linux或mac系统，会出现想楼主描述的这种情况，有时正常、有时异常，正常时返回的是一个溢出的数值

thinkersOne

转换异常了

cqzaiercn

五年过去了，是否有办法可以保证溢出的数值不会被反序列成一个错误的数？

hu-chia

问题似乎出在com.alibaba.fastjson.parser.JSONScanner#scanInt，这里的逻辑没有考虑数值溢出的情况，后续的逻辑也无从判断

hu-chia

[alibaba/fastjson]反序列化成Integer的疑惑

回答